JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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The sides of a triangle are

8 \mathrm{~cm}

10 \mathrm{~cm}

and

12 \mathrm{~cm}

. Then, the greatest angle is

View answer and explanation

Correct option: B

double of the smallest angle

Option B (double of the smallest angle) is correct because by using the cosine rule, we find that cos(C) = 1/8 and cos(A) = 3/4, and cos(2A) = 1/8, implying C = 2A.

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{p_1},{p_2},{p_3}

are altitudes of a

\Delta \;ABC

drawn from the vertices

A,B,C

and

\Delta

the area of the triangle, then

p_1^{ - 2} + p_2^{ - 2} + p_3^{ - 2}

is equal to If the sides of the triangles are

5k,\;6k,\;5k

and radius of incircle is 6, the value of

k

is equal to In a

\Delta \,ABC

, if

a = \left( {b - c} \right)\sec \theta

, then

\frac{{2\,\sqrt {bc} }}{{b - c}}\,\,\sin \,\,\frac{A}{2} =

\Delta \;ABC,\frac{{b + c}}{a}

is equal to If

\Delta = {a^2} - {\left( {b - c} \right)^2}

, where

\Delta

is the area of

\Delta \;ABC

, then

\tan A

is equal to If

A

is the area and

2 s

is the sum of the sides of a triangle, then