JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Easy

1 of 1

Application +4 | -1

In a

\Delta \,ABC

, if

a = \left( {b - c} \right)\sec \theta

, then

\frac{{2\,\sqrt {bc} }}{{b - c}}\,\,\sin \,\,\frac{A}{2} =

View answer and explanation

Correct option: C

\tan \,\,\theta

Option C (

\tan \,\,\theta

) is correct because by substituting

a = (b - c)\sec \theta

into the cosine rule and simplifying, we find that

\frac{{2\,\sqrt {bc} }}{{b - c}}\,\,\sin \,\,\frac{A}{2} = \tan \,\,\theta

More Questions from PROPERTIES OF TRIANGLES

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