JEE PHYSICS MCQ: THERMODYNAMICS

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\mathrm{\gamma }

is the ratio of specific heats and

R

is the universal gas constant, then the molar specific heat at constant volume

{C_v}

is given by

View answer and explanation

Correct option: C

\frac{R}{{\mathrm{\gamma } - 1}}

Option C (

\frac{R}{{\gamma - 1}}

) is correct because it is derived from Mayer's formula and the definition of the ratio of specific heats.

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