JEE PHYSICS MCQ: THERMODYNAMICS

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For adiabatic processes

\left( {\gamma = \frac{{{C_p}}}{{{C_v}}}} \right)

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Correct option: C

T{V^{\gamma - 1}} =

constant

Option C is correct because for adiabatic processes, the relation between temperature and volume is given by

T{V^{\gamma - 1}} = constant

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