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JEE MATHEMATICS MCQ: FUNCTIONS

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Analyzing +4 | -1
Let f(x)={0,      x=0x2sin⁡π/2x,      ∣x∣<1x∣x∣,      ∣x∣≥1.f\left( x \right) = \left\{ {\begin{array}{cccccccccccccccccccc} {\begin{array}{cccccccccccccccccccc} {0,\;\;\;x = 0}\\ {{x^2}\sin \pi /2x,\;\;\;\left| x \right| < 1} \end{array}}\\ {x\left| x \right|,\;\;\;\left| x \right| \ge 1} \end{array}} \right.. Then, f(x)f\left( x \right) is
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Correct option: B
An odd function
The correct answer is B (An odd function) because f(-x) = -f(x) for all x, satisfying the definition of an odd function.

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