JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

f:(-\infty, 2] \longrightarrow(-\infty, 4]

, where

f(x)=x(4-x)

, then

f^{-1}(x)

is given by:

View answer and explanation

Correct option: A

2-\sqrt{4-x}

The correct answer is A (

2-\sqrt{4-x}

) because it represents the inverse function of f(x) with the given domain and range.

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g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}

f(x + y) = f(x)f(y)

\sum\limits_{x = 1}^\infty {f(x) = 2,x,y \in N},

\frac{{f(4)}}{{f(2)}}