JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Medium

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Application +4 | -1

The tangent to the curve

y = 2{x^2} - x + 1

is parallel to the line

y = 3x + 9

at the point

View answer and explanation

Correct option: D

\left( {1,2} \right)

Option D ((1,2)) is correct because at this point, the derivative of the curve equals the slope of the line, indicating a parallel tangent.

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a

y=x^3-a x

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x y=1-y

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y^3-3 x y+2=0

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\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

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x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z