JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

Let

f:(4,6) \rightarrow(6,8)

be a function defined by

f(x)=x+\left[\frac{x}{2}\right]

, where [.] denotes the greatest integer function, then

f^{-1}(x)

is equal to

View answer and explanation

Correct option: C

x-2

Option C (

x-2

) is correct because it is the inverse function of f(x) = x + 2 on the given domain.

More Questions from FUNCTIONS

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

f(x)=x(4-x)

f^{-1}(x)

g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}