The electrolysis of a solution resulted in the formation of ${{\rm{H}}_2}$ at the cathode and ${\rm{C}}{{\rm{l}}_2}$ at the anode. The liquid is:

${{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4}$ solution

${\rm{CuC}}{{\rm{l}}_2}$ solution in water

NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

1 Easy

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Understanding +4 | -1

The electrolysis of a solution resulted in the formation of

{\mathrm{H}_2}

at the cathode and

\mathrm{C}{\mathrm{l}_2}

at the anode. The liquid is:

View answer and explanation

Correct option: C

\mathrm{NaCl}

solution in water

Option C (NaCl solution in water) is correct because electrolysis of NaCl(aq) produces H2 at the cathode and Cl2 at the anode.

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A{l^{3 + }}

{H_2}

{H^ + }

\mathrm{LiCl},{\rm{NaCl {\kern 1pt}{\kern 1pt}and {\kern 1pt}{\kern 1pt}KCl}}

\left(\mathrm{CuSO}_4\right)

\mathrm{A}{\mathrm{l}^{3 + }}