The correct order of molar conductivity at infinite dilution of ${\rm{LiCl}},{\rm{NaCl {\kern 1pt}{\kern 1pt}and {\kern 1pt}{\kern 1pt}KCl}}$ is

NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

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The correct order of molar conductivity at infinite dilution of

\mathrm{LiCl},{\rm{NaCl {\kern 1pt}{\kern 1pt}and {\kern 1pt}{\kern 1pt}KCl}}

View answer and explanation

Correct option: B

\mathrm{KCl} > NaCl > LiCl

Option B (

\mathrm{KCl} > NaCl > LiCl

) is correct because ionic mobility decreases with increasing hydrated size, and Li+ has the largest hydrated size among these ions.

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