JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

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Application +4 | -1

\mathrm{sec}\,\mathrm{\theta \; + }\,\mathrm{tan}\,\mathrm{\theta } = 1

, then root of the equation

\left( {a - 2b + c} \right){x^2}\,\, + \,\,\left( {b - 2c + a} \right)x\,\, + \,\,\left( {c - 2a + b} \right) = 0

View answer and explanation

Correct option: A

\sec \,\,\mathrm{\theta }

Option A (

\sec \theta

) is correct because one root of the quadratic equation is 1, and given the condition

\sec \theta + \tan \theta = 1

, it follows that

\sec \theta = 1

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