JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Medium

1 of 1

Application +4 | -1

\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=

View answer and explanation

Correct option: A

1-2 \cos \frac{A}{2} \cos \frac{B}{2} \sin \frac{C}{2}

Option A (

1-2 \cos \frac{{A}}{{2}} \cos \frac{{B}}{{2}} \sin \frac{{C}}{{2}}

) is correct because it is the result of applying trigonometric identities to simplify the given expression.

More Questions from TRIGONOMETRY RATIOS

Practice All Chapter MCQs →

\tan \alpha=\frac{p}{q}

\alpha=6 \beta

\alpha

\frac{1}{2}[p \operatorname{cosec} 2 \beta-q \sec 2 \beta]

\cos 12^{\circ}+\cos 84^{\circ}+\cos 156^{\circ}+\cos 132^{\circ}

\triangle A B C

C

{\sin ^6}\,\,\theta + {\cos ^6}\,\,\theta + 3{\sin ^2}\,\,\theta \,\,{\cos ^2}\,\,\theta

\sin ^2 \frac{A}{2}+\sin ^2 \frac{B}{2}+\sin ^2 \frac{C}{2}=

\frac{\sin 2 A}{1+\cos 2 A} \cdot \frac{\cos A}{1+\cos A}=