The rate of the reaction ${\rm{CC}}{{\rm{l}}_3}{\rm{CHO}} + {\rm{NO}} \to {\rm{CHC}}{{\rm{l}}_3} + {\rm{NO}} + {\rm{CO}}$ is equal to rate $k\left[ {{\rm{CC}}{{\rm{l}}_3}{\rm{CHO}}} \right]\left[ {{\rm{NO}}} \right]$. If concentration is expressed in mol/L. The unit of k is

${\rm{L}}\;{\rm{mo}}{{\rm{l}}^{ - 1}}\;{{\rm{s}}^{ - 1}}$

${\rm{mol}}\;{{\rm{L}}^{ - 1}}\;{{\rm{s}}^{ - 1}}$

${{\rm{L}}^2}\;{\rm{mo}}{{\rm{l}}^{ - 2}}\;{{\rm{s}}^{ - 1}}$

NEET UG CHEMISTRY MCQ: CHEMICAL KINETICS

1 Easy

1 of 1

Application +4 | -1

The rate of the reaction

\mathrm{CC}{\mathrm{l}_3}\mathrm{CHO} + \mathrm{NO} \to \mathrm{CHC}{\mathrm{l}_3} + \mathrm{NO} + \mathrm{CO}

is equal to rate

k\left[ {\mathrm{CC}{\mathrm{l}_3}\mathrm{CHO}} \right]\left[ {\mathrm{NO}} \right]

.

If concentration is expressed in mol/L. The unit of k is

View answer and explanation

Correct option: A

\mathrm{L}\;\mathrm{mo}{\mathrm{l}^{ - 1}}\;{\mathrm{s}^{ - 1}}

Option A (

\mathrm{L}\;\mathrm{mo}{\mathrm{l}^{ - 1}}\;{\mathrm{s}^{ - 1}}

) is correct because it is the unit of the rate constant for a second-order reaction.