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NEET UG CHEMISTRY MCQ: CHEMICAL KINETICS

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The rate constant (k′)\left( {k'} \right) of one of the reaction is found to be double that of the rate constant (k′′)\left( {k''} \right) of another reaction. Then the relationship between the corresponding activation energies of the two reaction (E′a  and  E′′a)\left( {{{E'}_a}\;\mathrm{and}\;{{E''}_a}} \right) can be represented as
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Correct option: D
E′a<E′′a{{E'}_a} < {{E''}_a}
Option D (E′a<E′′a{{E'}_a} < {{E''}_a}) is correct because a higher rate constant implies a lower activation energy, according to the Arrhenius equation.

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