Resistance of 0.2 M solution of an electrolyte is $50{\kern 1pt} {\kern 1pt} \Omega $ . The specific conductance of the solution is 1.3 S ${{\rm{m}}^{ - 1}}$. If resistance of the 0.4 M solution of the same electrolyte is 260Ω , its molar conductivity is

$6.25 \times {10^{ - 4}}{\rm{S}}{\kern 1pt} {\kern 1pt} {{\rm{m}}^2}{\rm{mo}}{{\rm{l}}^{ - 1}}$

$6250{\kern 1pt} {\kern 1pt} {\rm{S}}{\kern 1pt} {\kern 1pt} {{\rm{m}}^2}{\rm{mo}}{{\rm{l}}^{ - 1}}$

$625 \times {10^{ - 4}}{\rm{S}}{\kern 1pt} {\kern 1pt} {{\rm{m}}^2}{\rm{mo}}{{\rm{l}}^{ - 1}}$

$62.5{\kern 1pt} {\kern 1pt} {\kern 1pt} {\rm{S}}{\kern 1pt} {\kern 1pt} {{\rm{m}}^2}{\rm{mo}}{{\rm{l}}^{ - 1}}$

NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

1 Hard

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Application +4 | -1

Resistance of 0.2 M solution of an electrolyte is

50{\kern 1pt} {\kern 1pt} \Omega

. The specific conductance of the solution is 1.3 S

{\mathrm{m}^{ - 1}}

.
If resistance of the 0.4 M solution of the same electrolyte is 260Ω , its molar conductivity is

View answer and explanation

Correct option: B

6.25 \times {10^{ - 4}}\mathrm{S}{\kern 1pt} {\kern 1pt} {\mathrm{m}^2}\mathrm{mo}{\mathrm{l}^{ - 1}}

Option B (

6.25 \times {10^{ - 4}}\mathrm{S}{\kern 1pt} {\kern 1pt} {\mathrm{m}^2}\mathrm{mo}{\mathrm{l}^{ - 1}}

) is correct because it correctly calculates the molar conductivity using the given resistance and specific conductance.