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JEE MATHEMATICS MCQ: TANGENTS & NORMALS

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If the curves x2a2+y2b2=1 and x2l2−y2m2=1\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1\,and\,\frac{{{x^2}}}{{{l^2}}} - \frac{{{y^2}}}{{{m^2}}} = 1 cut each other orthogonally, then
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Correct option: C
a2−b2=l2+m2{a^2} - {b^2} = {l^2} + {m^2}
Option C (a2−b2=l2+m2{a^2} - {b^2} = {l^2} + {m^2}) is correct because it is derived from the condition for orthogonal intersection of the two given curves.

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