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JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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A cup of tea cools from 70∘C70^{\circ} {C} to 60∘C60^{\circ} {C} in 5 minutes and to 50∘C50^{\circ} {C} in next 7 minutes. Assuming Newton's law of cooling, the temperature of surroundings is
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Correct option: C
30∘C30^{\circ} {C}
Option C (30∘C30^{\circ} {C}) is correct because it is derived from Newton's law of cooling by setting up and solving a system of equations.

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