JEE PHYSICS MCQ: OSCILLATIONS

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Application +4 | -1

A spring compressed by

0.2 \mathrm{~m}

develops a restoring force of

25 \mathrm{~N}

. A body of mass

5 \mathrm{~kg}

is placed over it. Deduce:
(i) force constant of the spring
(ii) the depression of the spring under the weight of the body and
(iii) the period of oscillation, if the body is disturbed.
Take

g=10 \mathrm{~N} \mathrm{~kg}^{-1}

View answer and explanation

Correct option: A

125 \mathrm{~Nm}^{-1}; 0.4 \mathrm{~m}; \frac{2 \pi}{5} \mathrm{~s}

Option A (

125 \mathrm{~Nm}^{-1}; 0.4 \mathrm{~m}; \frac{2 \pi}{5} \mathrm{~s}

) is correct because it correctly calculates the spring constant, depression, and period of oscillation.

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{y_1}

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{y_2}

its potential energy is

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