If $f(x)=x^{3 / 2}(3 x-10), x \geq 0$, then $f(x)$ is increasing in

JEE MATHEMATICS MCQ: INCREASING & DECREASING

1 Easy

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Analyzing +4 | -1

f(x)=x^{3 / 2}(3 x-10), x \geq 0

, then

f(x)

is increasing in

View answer and explanation

Correct option: B

[2, \infty)

The correct answer is B (

[2, \infty)

) because the derivative

f'(x)

is non-negative for

x \geq 2

, indicating that

f(x)

is increasing on that interval.

Practice All Chapter MCQs →

f\left( x \right) = \frac{{K\sin x + 2\cos x}}{{\sin x + \cos x}}

x

f\left( x \right) = {x^2} + ax + 1

a

f(x)=

\sin x-\cos x-a x+b

f(x)=x e^{x(1-x)}, x \in R

f

g

fog

f\left( x \right) = {x^3} + b{x^2} + cx + d

0 < {b^2} < c

\left( { - \infty ,\;\infty } \right)