The function $f$ defined by $f(x)=(x+2) e^{-x}$ is

Decreasing in $(-\infty,-1)$ and increasing in $(-1, \infty)$

JEE MATHEMATICS MCQ: INCREASING & DECREASING

1 Medium

1 of 1

Analyzing +4 | -1

The function

f

defined by

f(x)=(x+2) e^{-x}

View answer and explanation

Correct option: D

Decreasing in

(-1, \infty)

and increasing in

(-\infty,-1)

Option D (Decreasing in

(-1, \infty)

and increasing in

(-\infty,-1)

) is correct because the derivative is negative on

(-1, \infty)

and positive on

(-\infty,-1)

Practice All Chapter MCQs →

f\left( x \right) = \frac{{K\sin x + 2\cos x}}{{\sin x + \cos x}}

x

f\left( x \right) = {x^2} + ax + 1

a

f(x)=

\sin x-\cos x-a x+b

f(x)=x e^{x(1-x)}, x \in R

f

g

fog

f\left( x \right) = {x^3} + b{x^2} + cx + d

0 < {b^2} < c

\left( { - \infty ,\;\infty } \right)