In case of nitrogen, ${\rm{NC}}{{\rm{l}}_3}$ is possible but not ${\rm{NC}}{{\rm{l}}_5}$ while in case of phosphorus, ${\rm{PC}}{{\rm{l}}_3}$ as well as ${\rm{PC}}{{\rm{l}}_5}$ are possible. It is due to

Lower electronegativity of P but not in N

Lower tendency of H bond formation in P than N

Occurrence of P in solid while N in gaseous state at room temperature

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JEE CHEMISTRY MCQ: P-BLOCK ELEMENTS

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Understanding +4 | -1

In case of nitrogen,

\mathrm{NC}{\mathrm{l}_3}

is possible but not

\mathrm{NC}{\mathrm{l}_5}

while in case of phosphorus,

\mathrm{PC}{\mathrm{l}_3}

as well as

\mathrm{PC}{\mathrm{l}_5}

are possible. It is due to

View answer and explanation

Correct option: C

Availability of vacant d-orbital in P but not in N

Option C (Availability of vacant d-orbital in P but not in N) is correct because phosphorus has vacant d-orbitals that allow it to expand its octet and form five bonds, while nitrogen does not have d-orbitals and cannot exceed four bonds.

More Questions from P-BLOCK ELEMENTS

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The gas used for inflating the tyres of aeroplanes is: Which of the following is correct stability order of oxides of

17^{\text {th }}

group elements is: Assertion: Ozone is a powerful oxidising agent in comparison to

{O}_2

.

Reason: Ozone is diamagnetic but

{O}_2

is paramagnetic. Which of the following is kept in water?

\mathrm{C}{\mathrm{N}^ - }

ion and

{\mathrm{N}_2}

are isoelectronic but in contrast to

\mathrm{C}{\mathrm{N}^ - },\mathrm{\;}{\mathrm{N}_2}

is chemically inert because of: Consider the following statements

(i) Reaction

2 {Fe}^{3+}+{SO}_2+2 {H}_2 {O} \rightarrow 2 {Fe}^{2+}+{SO}_4^{2-}+4 {H}^{+}

shows reducing character of sulphur dioxide

(ii)

{H}_2 {~S}_2 {O}_8

contains four

{S}={O}

, two

{S}-{OH}

and one

{O}-

{O}

bond

(iii)

{NH}_3

gas can be dried effectively by using conc.

{H}_2 {SO}_4

.

(iv) One of the major use of

{H}_2 {SO}_4

is in the manufacture of fertilizers.

Which of the following is the correct code for the statements above?