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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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∫sin⁡2x1+sin⁡2xdx=\int \frac{\sin 2 x}{1+\sin ^2 x} d x=
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Correct option: B
log⁡(1+sin⁡2x)+c\log \left(1+\sin ^2 x\right)+c
Option B (log⁡(1+sin⁡2x)+c\log \left(1+\sin ^2 x\right)+c) is correct because the derivative of 1+sin⁡2x1+\sin^2 x is sin⁡2x\sin 2x, which is present in the integrand.

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