JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1

\int {e}^{{x}^2}\left(2-\frac{1}{{x}^2}\right) {de}={e}^{{x}^2} {f}({x})+{C}

and

{f}\left(\frac{1}{2}\right)=2

, then

f(1)

is equal to (where

{C}

is an arbitrary constant)

View answer and explanation

Correct option: A

Option A (1) is correct because after integrating and comparing with the given form, f(x) is found to be 1/x, and f(1) equals 1.

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