JEE CHEMISTRY MCQ: AMINES

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Hinsberg’s reagent is

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Correct option: C

{C_6}{H_5}S{O_2}Cl

Option C (

{C_6}{H_5}S{O_2}Cl

) is correct because Hinsberg’s reagent is benzene sulphonyl chloride, used to distinguish between primary, secondary, and tertiary amines.

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\mathrm{Z}

' in the sequence

{{\text{C}}_6}{{\text{H}}_5}{\text{N}}{{\text{H}}_2}\xrightarrow{{{\text{NaN}}{{\text{O}}_2} + {\text{HCl}}}}{\text{X}}\xrightarrow{{{\text{CuCN}}}}{\text{Y}}\xrightarrow{{{{\text{H}}^ + }/{{\text{H}}_2}{\text{O}}}}{\text{Z}}

The primary, secondary and tertiary amines can be distinguished by: Assertion: The main product of reaction of alcoholic silver nitrite and ethyl bromide is nitroethane.

Reason: Silver nitrite is predominantly covalent compound. Hofmann’s bromamide reaction is to convert Gabriel phthalamide synthesis is used for preparation of :- Elements found in explosive are: