JEE CHEMISTRY MCQ: AMINES

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Aniline is weaker base than ethylamine because:

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Correct option: A

Lone pair of electrons of N-atom is not freely available for coordination with a proton due to resonance than in ethylamine

Option A is correct because the lone pair of electrons on the nitrogen atom in aniline is delocalized into the benzene ring through resonance, making it less available for protonation compared to ethylamine.

More Questions from AMINES

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Identify '

\mathrm{Z}

' in the sequence

{{\text{C}}_6}{{\text{H}}_5}{\text{N}}{{\text{H}}_2}\xrightarrow{{{\text{NaN}}{{\text{O}}_2} + {\text{HCl}}}}{\text{X}}\xrightarrow{{{\text{CuCN}}}}{\text{Y}}\xrightarrow{{{{\text{H}}^ + }/{{\text{H}}_2}{\text{O}}}}{\text{Z}}

The primary, secondary and tertiary amines can be distinguished by: Assertion: The main product of reaction of alcoholic silver nitrite and ethyl bromide is nitroethane.

Reason: Silver nitrite is predominantly covalent compound. Hofmann’s bromamide reaction is to convert Gabriel phthalamide synthesis is used for preparation of :- Elements found in explosive are: