What is ${P^H}$ of 0.02 M solution of ammonium chloride at ${25^{\rm{o}}}C\,\,\,\,\left( {{K_b}\,\,{\rm{ of }}\,\,N{H_3} = 1.8 \times {{10}^{ - 5}}} \right)$

NEET UG CHEMISTRY MCQ: Equilibrium

1 Hard

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Application +4 | -1

What is

{P^H}

of 0.02 M solution of ammonium chloride at

{25^\mathrm{o}}C\,\,\,\,\left( {{K_b}\,\,\mathrm{ of }\,\,N{H_3} = 1.8 \times {{10}^{ - 5}}} \right)

View answer and explanation

Correct option: A

5.477

Option A (5.477) is correct because it is the pH calculated using the hydrolysis constant and concentration of the ammonium chloride solution.

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Mg{(HC{O_3})_2}

MgC{O_3}

Mg{(OH)_2}

MgC{O_3}

K_{\mathrm{P}}

\mathrm{CaCO}_3

4.5 \times 10^{-2}

\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}),

K_{\mathrm{P}}

2.0 \mathrm{~atm}.

\mathrm{CaO}

\mathrm{CaCO}_3

+

\leftrightharpoons

\mathrm{PC}{\mathrm{l}_5}\leftrightharpoons\mathrm{PC}{\mathrm{l}_3} + \mathrm{C}{\mathrm{l}_2}

{K_{\mathrm{eq}}} = 0.41

\mathrm{p}{K_a}