For ${\rm{PC}}{{\rm{l}}_5}\leftrightharpoons{\rm{PC}}{{\rm{l}}_3} + {\rm{C}}{{\rm{l}}_2}$, initial concentration of each reactant and product is 1 M. If ${K_{{\rm{eq}}}} = 0.41$ then

More ${\rm{PC}}{{\rm{l}}_5}$ will form

More ${\rm{PC}}{{\rm{l}}_3}$ will form

More ${\rm{C}}{{\rm{l}}_2}$ will form

Back to Equilibrium

NEET UG CHEMISTRY MCQ: Equilibrium

1 Medium

1 of 1

Application +4 | -1

For

\mathrm{PC}{\mathrm{l}_5}\leftrightharpoons\mathrm{PC}{\mathrm{l}_3} + \mathrm{C}{\mathrm{l}_2}

, initial concentration of each reactant and product is 1 M. If

{K_{\mathrm{eq}}} = 0.41

then

View answer and explanation

Correct option: C

\mathrm{PC}{\mathrm{l}_5}

will form

Option C (More PCl5 will form) is correct because the reaction quotient Q is greater than Keq, indicating the reaction will shift to the left to form more PCl5.

More Questions from Equilibrium

Practice All Chapter MCQs →

Given below are two statements: One is labelled as Assertion A and the other labelled as Reason R.
Assertion A: During the boiling of water having temporary hardness,

Mg{(HC{O_3})_2}

is converted to

MgC{O_3}

.
Reason R The solubility product of

Mg{(OH)_2}

is greater than that of

MgC{O_3}

.
In the light of the above statements, choose the most appropriate answer from the options given below At a certain temperature,

K_{\mathrm{P}}

for the dissociation of solid

\mathrm{CaCO}_3

4.5 \times 10^{-2}

atm and for the reaction

\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}),

the

K_{\mathrm{P}}

value is

2.0 \mathrm{~atm}.

The pressure of carbon monoxide at this temperature, when solid carbon

\mathrm{CaO}

and

\mathrm{CaCO}_3

are mixed together and allowed to attain equilibrium is Phenolphthalein shows … in acid medium. At the state of dynamic equilibrium, for solute

+

solvent

\leftrightharpoons

solution. Select the

\mathrm{p}{K_a}

value of the strongest acid from the following Which can act as buffer?