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JEE MATHEMATICS MCQ: FUNCTIONS

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Let f(x)=min⁡{x,  x2},  f\left( x \right) = \min \left\{ {x,\;{x^2}} \right\},\; for every x∈R.x \in R. . Then,
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Correct option: A
f(x)={x,      x≥1x2,      0≤x<1x,      x<0f\left( x \right) = \left\{ {\begin{array}{cccccccccccccccccccc} {\begin{array}{cccccccccccccccccccc} {x,\;\;\;x \ge 1}\\ {{x^2},\;\;\;0 \le x < 1} \end{array}}\\ {x,\;\;\;x < 0} \end{array}} \right.
Option A is correct because it accurately represents the minimum value between x and x² for different ranges of x, considering x >= 1, 0 <= x < 1, and x < 0.

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