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JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1
If g:(−∞,∞)→(−π2,π2),g(x)=2tan⁡−1(eπ)−π2g:(-\infty, \infty) \rightarrow\left(\frac{-\pi}{2}, \frac{\pi}{2}\right), g(x)=2 \tan ^{-1}\left(e^\pi\right)-\frac{\pi}{2} and ff is inverse of gg, then f(0)=……f(0)=\ldots \ldots
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Correct option: A
1
Option A (1) is correct because after finding the inverse function and differentiating it, substituting x=0 gives the value 1.

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