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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1
∫ex(x2+1)(x+1)2dx=\int e^x \frac{\left(x^2+1\right)}{(x+1)^2} d x=
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Correct option: A
(x−1x+1)ex+c\left(\frac{x-1}{x+1}\right) e^x+c
Option A is correct because the integral can be expressed in the form ∫ex[f(x)+f′(x)]dx\int e^x [f(x) + f'(x)] dx, where f(x)=x−1x+1f(x) = \frac{x-1}{x+1} and f′(x)=2(x+1)2f'(x) = \frac{2}{(x+1)^2}.

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