JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

For

x \in \mathbb{R}

, two real valued functions

f(x)

and

g(x)

are such that,

g(x)=\sqrt{x}+1

and

fog(x)=x+3-\sqrt{x}

. Then

f(0)

is equal to

View answer and explanation

Correct option: B

Option B (5) is correct because by substituting

t = \sqrt{x} + 1

into the given functional equation, we can find

f(t)

and then evaluate

f(0)

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