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JEE MATHEMATICS MCQ: RELATIONS

1 Easy

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Understanding +4 | -1

Let

P=\left\{(x, y):\left|x^2+y^2\right|=1, x, y \in R\right\}

. Then

\mathrm{P}

is

View answer and explanation

Correct option: B

Symmetric

Option B (Symmetric) is correct because if

(x, y) \in P

, then

|x^2 + y^2| = 1

, which implies

|y^2 + x^2| = 1

, so

(y, x) \in P

.

More Questions from RELATIONS

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\mathrm{Z}

of all integers, which of the following relation

R

is not an equivalence relation? Let

\mathrm{N}

denote the set of all natural numbers and

\mathrm{R}

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\mathrm{N} \times \mathrm{N}

(\mathrm{a}, \mathrm{b}) \mathrm{R}(\mathrm{c}, \mathrm{d})

a d(b+c)=b c(a+d)

\mathrm{R}

W

denote the words in the English dictionary. Define the relation

R

R=\{(x, y) \in W \times W \mid

x

y

have at least one letter in common

\}

S

be the set of all real numbers. Then, the relation

R = \{ \left( {a,\;b} \right):1 + ab > 0\}

S

X

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R

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X

A

is disjoint from

B

R

R

N

R = \left\{ {\left( {x,\;y} \right):4x + 3y = 20} \right\}

. Which of the following belongs to

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