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JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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The freezing point a thermometer is marked as 20∘20^\circ and the boiling point as 150∘.150^\circ . A temperature of 60∘C60^\circ C on this thermometer will be read as
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Correct option: C
98∘98^\circ
Option C (98∘98^\circ) is correct because it is the corresponding temperature on the new thermometer scale calculated using the formula C−O100=X−LU−L\frac{{C - O}}{{100}} = \frac{{X - L}}{{U - L}}.

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