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JEE MATHEMATICS MCQ: 2D GEOMETRY SYSTEM

1 Easy
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Application +4 | -1
Three distinct points A,BA, B and CC are given in the 2-dimensional coordinates plane such that the ratio of the distance of any one of them from the point (1,0)(1,0) to the distance from the point (−1,0)(-1,0) is equal to 13\frac{1}{3}. Then, the circumcentre of the triangle ABCA B C is at the point
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Correct option: A
(54,0)\left(\frac{5}{4}, 0\right)
Option A (54,0)\left(\frac{5}{4}, 0\right) is correct because the circumcentre of the triangle is the center of the circle defined by the given condition.

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