JEE MATHEMATICS MCQ: 2D GEOMETRY SYSTEM

1 Easy

1 of 1

Application +4 | -1

The area of the quadrilateral with its vertices at the foci of the conics

9 x^2-16 y^2-18 x+32 y-23

=0

and

25 x^2+9 y^2-50 x-18 y+33=0

, is

View answer and explanation

Correct option: B

\frac{8}{9}

Option B

\frac{8}{9}

is correct because calculating the foci of both conics and then finding the area of the quadrilateral formed by them gives this result.

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\alpha

(\alpha, 2 \alpha)

\Delta A B C

A(0,2), B(2,0)

C(4,4)

P

2 P A=3 P B

A

(0,0)

B

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(1, \sqrt{3}),(0,0)

(2,0)

(1,5),(-3,1) \,\&\,(-2,1)

(0,0)(3,0)

(0,4)

A B C

A(-1,0), B\left(-2, \frac{3}{4}\right)

C\left(-3,-\frac{7}{6}\right)

H

B C H