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JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Remembering +4 | -1

\sum_{n=12}^4 \sin \left(\frac{\pi}{2}\right)

is equal to

View answer and explanation

Correct option: D

\frac{\sqrt{3}+\sqrt{2}+2}{2}

Option D (

\frac{\sqrt{3}+ \sqrt{2}+2}{2}

) is correct because it is the sum of

\sin{\frac{\pi}{1}}

,

\sin{\frac{\pi}{2}}

,

\sin{\frac{\pi}{3}}

, and

\sin{\frac{\pi}{4}}

.

More Questions from TRIGONOMETRY RATIOS

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\tan \alpha=\frac{p}{q}

\alpha=6 \beta

\alpha

being an acute angle, then

\frac{1}{2}[p \operatorname{cosec} 2 \beta-q \sec 2 \beta]

is equal to The value of

\cos 12^{\circ}+\cos 84^{\circ}+\cos 156^{\circ}+\cos 132^{\circ}

\triangle A B C

is acute angled at

C

, then The value of the expression

{\sin ^6}\,\,\theta + {\cos ^6}\,\,\theta + 3{\sin ^2}\,\,\theta \,\,{\cos ^2}\,\,\theta

\sin ^2 \frac{A}{2}+\sin ^2 \frac{B}{2}+\sin ^2 \frac{C}{2}=

\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=