JEE MATHEMATICS MCQ: MAXIMA & MINIMA

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Analyzing +4 | -1

For

x \in\left(0, \frac{5 \pi}{2}\right)

, define

f(x)=\int_0^x \sqrt{t} \sin t d t

. Then

f

has

View answer and explanation

Correct option: C

local maximum at

\pi

and local minimum at

2 \pi

The function f(x) has a local maximum at

\pi

and a local minimum at

2\pi

because the sign of f'(x) changes from positive to negative at

\pi

and from negative to positive at

2\pi

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m(b)

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p

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