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JEE MATHEMATICS MCQ: MAXIMA & MINIMA

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Analyzing +4 | -1
Let f(x)=(1+b2)x2+2bx+1f(x)=\left(1+b^2\right) x^2+2 b x+1. Let m(b)m(b) be the minimum value of f(x)f(x) (that is least value). As bb varies, the range of m(b)m(b) is
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Correct option: D
(0,1](0,1]
Option D ((0,1]) is correct because the range of the minimum value function m(b) is calculated using calculus and analysis of the function's behavior.

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