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JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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Application +4 | -1
Suppose you want to cool 200g of lemon water (Specific heat 4200 J kg−1K−1)4200\,{\text{J}}\,{\text{k}}{{\text{g}}^{ - 1}}{{\text{K}}^{ - 1}}) at 30∘C30^\circ C by adding ice at −10∘C.- 10^\circ C. The amount of ice that should be added, so that the final temperature becomes 0∘C0^\circ C with all ice melt is
(Specific heat of ice = 2000 J kg−1K−1)2000\,{\text{J}}\,{\text{k}}{{\text{g}}^{ - 1}}{{\text{K}}^{ - 1}})
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Correct option: D
71 g
Option D (71 g) is correct because it is the amount of ice required to cool the lemon water to 0°C, calculated by equating heat gained by ice to heat lost by lemon water.

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