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JEE PHYSICS MCQ: OSCILLATIONS

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A circular disc rotating with frequency f0=1.3f_0=1.3 rev/sec comes to a stop in 30 seconds. The approximate angular acceleration is:
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Correct option: B
−0.27 rad/sec2-0.27 \mathrm{~rad} / \mathrm{sec}^2
Option B (-0.27 rad/sec²) is correct because it accurately calculates the angular acceleration using the given initial frequency and the time it takes to stop.

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