\[\smallint \frac{{\sec \,\,x}}{{\sec \,\,x\,\, + \,\,\tan x}}\,\,\;dx\] is equal to

$\sec \,\,x\,\, + \,\,\tan \,\,x + c$

$\log \,\,\sin \,\,x + \log \,\,\cos \,\,x + c$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\int \frac{{\sec \,\,x}}{{\sec \,\,x\,\, + \,\,\tan x}}\,\,\;dx

is equal to

View answer and explanation

Correct option: A

\tan \,\,x - \sec \,\,x + c

Option A (

\tan \,x - \sec \,x + c

) is correct because it is obtained by multiplying the numerator and denominator by

(\sec x - \tan x)

and then integrating the resulting expression.