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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy
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Application +4 | -1
If ∣z2−1∣=∣z∣2+1\left| {{z^2} - 1} \right| = {\left| z \right|^2} + 1, then zz lies on
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Correct option: B
The imaginary axis
Option B (The imaginary axis) is correct because the given condition implies that the argument of z2z^2 is π\pi, which means the argument of z is π2\frac{\pi}{2}, indicating that z lies on the imaginary axis.

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