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JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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Application +4 | -1
The ratio of Coulomb's electrostatic force to the gravitational force between an electron and a proton separated by some distance is 2.4×10392.4 \times 10^{39}. The ratio of the proportionality constant, K=14πε0K=\frac{1}{4 \pi \varepsilon_0} to the Gravitational constant GG is nearly

(Given that the charge of the proton and electron each =1.6×10−19C=1.6 \times 10^{-19} \mathrm{C}, the mass of the electron =9.11×10−31 kg=9.11 \times 10^{-31} \mathrm{~kg}, the mass of the proton =1.67×10−27 kg=1.67 \times 10^{-27} \mathrm{~kg})
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Correct option: B
102010^{20}
Option B (102010^{20}) is the correct order of magnitude for the ratio of the proportionality constant K to the gravitational constant G, based on the given ratio of electrostatic and gravitational forces.

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