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JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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Application +4 | -1
In a region, the potential is represented by V(x,y,z)=6x−8xy−8y+6yz,V(x, y, z)=6 x-8 x y-8 y+6 y z, where VV is in volts and x,y,zx, y, z are in metres. The electric force experienced by a charge of 2 C2 \mathrm{~C} situated at point (1,1,1)(1,1,1) is
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Correct option: D
435 N4 \sqrt{35} \mathrm{~N}
Option D (4354 \sqrt{35} N) is correct because the electric force is calculated by finding the electric field components and then using F=qEF = qE.

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