JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Hard

1 of 1

Analyzing +4 | -1

Let

a, b

be two real numbers such that

a b < 0

. If the complex number

\frac{1+a i}{b+i}

is of unit modulus and

a+

i b

lies on the circle

|z-1|=|2 z|

, then a possible value of

\frac{1+[a]}{4 b}

, where

[t]

is greatest integer function is:

View answer and explanation

Correct option: C

-\frac{1}{2}

The correct answer is C (

-\frac{1}{2}

) because it is obtained by using the given conditions to find the values of a and b, and then evaluating the expression.

More Questions from COMPLEX NUMBERS

Practice All Chapter MCQs →

{\left| {1 - i} \right|^x} = {2^x}

|z|=1

z \neq \pm 1

z, \frac{z}{1-z^2}

\left|z_r-r\right| \leq r, \forall r=1,2,3, \ldots, n

\left|\sum\limits_{r=1}^n z_r\right|

(z+a b)^3=a^3

a \neq 0

\alpha, \beta

\gamma

|\alpha-\beta|

{z^2} + {\left| z \right|^2} = 0,

z \in C

2x = - 1 + \sqrt 3 i

{\left( {1 - {x^2} + x} \right)^6} - {\left( {1 - x + {x^2}} \right)^6}