JEE MATHEMATICS MCQ: STRAIGHT LINES

1 Easy

1 of 1

Application +4 | -1

(\sin \theta, \cos \theta), \theta \in[0,2 \pi]

and

(1,4)

lie on the same side or on the line

\sqrt{3} x-y+1=0

, then the maximum value of

\sin \theta

will be ______.

View answer and explanation

Correct option: A

Option A (0) is correct because the maximum value of

\sin \theta

is 0 when

\theta

lies in the interval

[\frac{{4\pi}}{{3}}, 2\pi]

based on the given inequality.

More Questions from STRAIGHT LINES

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x-3 y=p, a x+2 y=q

a x+y=r

\left\{ {a{t_1}{t_2},\;a\left( {{t_1} + {t_2})\} ,\{ a{t_2}{t_3},a({t_2} + {t_3}} \right)} \right\},\;\left\{ {a{t_3}{t_1},\;a\left( {{t_3} + {t_1}} \right)} \right\}

y = 2\;x + 4

6x = 3y + 5

{x^2} + {y^2} + 2xy - 8ax - 8ay - 9{a^2} = 0

(3,8)

x+3 y=7

\left( {{x^2} + 7xy + 2{y^2}} \right)\left( {y - 1} \right) = 0