Skip to main content
Back to STRAIGHT LINES

JEE MATHEMATICS MCQ: STRAIGHT LINES

1 Easy
1 of 1
Application +4 | -1
Find the image of the point (3,8)(3,8) with respect of the line x+3y=7x+3 y=7 assuming the line to be plane mirror:
View answer and explanation
Correct option: B
(−1,−4)(-1,-4)
Option C ((-1,-4)) is correct because it is the correct image point calculated using the mirror formula.

More Questions from STRAIGHT LINES

Practice All Chapter MCQs →
If the three lines x−3y=p,ax+2y=qx-3 y=p, a x+2 y=q and ax+y=ra x+y=r form a right-angled triangle then :
The orthocentre of the triangle whose vertices are

{at1t2,  a(t1+t2)},{at2t3,a(t2+t3)},  {at3t1,  a(t3+t1)}\left\{ {a{t_1}{t_2},\;a\left( {{t_1} + {t_2})\} ,\{ a{t_2}{t_3},a({t_2} + {t_3}} \right)} \right\},\;\left\{ {a{t_3}{t_1},\;a\left( {{t_3} + {t_1}} \right)} \right\} is
 The distance between the parallel lines y=2  x+4y = 2\;x + 4 and 6x=3y+56x = 3y + 5 is The distance between the pair of lines given by x2+y2+2xy−8ax−8ay−9a2=0{x^2} + {y^2} + 2xy - 8ax - 8ay - 9{a^2} = 0 is The centroid of the triangle whose three sides are given by the combined equation (x2+7xy+2y2)(y−1)=0\left( {{x^2} + 7xy + 2{y^2}} \right)\left( {y - 1} \right) = 0 is A line LL passes through the points (1,1)(1,1) and (2,0)(2,0) and another line L′L^{\prime} passes through (12,0)\left(\frac{1}{2}, 0\right) and perpendicular to LL. Then the area of the triangle formed by the lines L,L′L, L^{\prime} and y−y- axis, is NN. Find 16N16 N
Type at least 2 characters or jump directly:
🩺 NEET MCQs 🔬 JEE MCQs 🎯 JEE College Predictor Study guides 📊 Dashboard
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.

Continue with Free Account →