JEE MATHEMATICS MCQ: FUNCTIONS

1 Hard

1 of 1

Application +4 | -1

Let the function

f\left( x \right) = 3{x^2} - 4x + 5\log \left( {1 + \left| x \right|} \right)

be defined on the interval

\left[ {0,1} \right].

The even extension of f(x) to the interval

\left[ { - 1,1} \right]

View answer and explanation

Correct option: A

3{x^2} + 4x + 8\log \left( {1 + \left| x \right|} \right)

The correct answer is A (

3{x^2} + 4x + 8\log ( {1 + \left| x \right|} )

) because the even extension involves replacing x with -x for negative values and simplifying.

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