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JEE MATHEMATICS MCQ: SYSTEM OF CIRCLES

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The value of kk so that x2+y2+kx+4y+2=0x^2+y^2+k x+4 y+2=0 and 2(x2+y2)−4x−3y+k=02\left(x^2+y^2\right)-4 x-3 y+k=0 cut orthogonally, is
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Correct option: C
−103\frac{-10}{3}
Option C (−103\frac{-10}{3}) is correct because the condition for orthogonal intersection of two circles (2(g1g2+f1f2)=c1+c22(g_1g_2 + f_1f_2) = c_1 + c_2) is applied to find the value of kk.

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