JEE MATHEMATICS MCQ: SYSTEM OF CIRCLES

1 Easy

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Application +4 | -1

If the circles

{x^2} + {y^2} + 2ky + 2x + 6 = 0

and

{x^2} + {y^2} + 2ky + k = 0

intersects orthogonally. Then, the value of

k

View answer and explanation

Correct option: C

- \frac{3}{2}

Option C (

- \frac{3}{2}

) is correct because it is one of the values of k obtained by solving the quadratic equation derived from the orthogonality condition of the circles.

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